Update ANS: Class 9 ICSE SELINA EX 10A question 15 | In a triangle ABC angle ANC=90 and P is a point on AC such that PBC = PCB show that : PA=PB

13 Jul 2019

Class 9 ICSE SELINA EX 10A question 15 | In a triangle ABC angle ANC=90 and P is a point on AC such that PBC = PCB show that : PA=PB

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