14 Jul 2019

x=cosθ+θsinθ y=sinθ-θcosθ find d2x/dy2

x=cosθ+θsinθ y=sinθ-θcosθ prove that d2y/dx2

x=cosθ+θsinθ y=sinθ-θcosθ find d2x/dy2 Ankit

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