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9 Oct 2019

sin−1(6x)+sin−1(6√3x)=−π2 solve

at October 09, 2019

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Labels: Class 12, Inverse Trigonometry, Math Questions

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If a-b=3,a+b+x=2, then the value of (a-b)[x^3-2ax^2+a^2x-(a+b)b^2] is

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