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8 Oct 2019

tan^-1(1/2tan 2A)+tan^-1(cotA)+tan^-1(cot^3A) = 0

tan^-1(1/2tan 2A)+tan^-1(cotA)+tan^-1(cot^3A) updateans = 0

at October 08, 2019

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Labels: Class 12, Inverse Trigonometry, Math Questions

1 comment:

Mr. Kumar9 October 2019 at 10:33
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