Let, A,B,C are three side of a triangle than
Condition 1 - A+B+C < 13
Condition 2 - A,B,C > 1
Condition 3. Sum of the smaller side must be greater than the largest side => A+B > C
as Perimeter is less than 13 than longer side must be less than 13/2= 6.5
Why?
A+B > C
A+B+C > 2C
C<(A+B+C)/2 < semi perimeter.
now, replacing A,B,C with (6-P), (6-Q), (6-R)
so, (6-P)+(6-Q)+(6-R) < 13
P+Q+R > 5
so solution is
1. 2,2,2
2. 2,2,3
3. 3,2,4
4. 3,3,3
5. 3,3,4
6. 3,3,5
7. 4,3,4
8. 4,3,5
9. 4,4,2
10. 4,4,4
11. 5,2,4
12. 5,2,5
there are twelve triangle,
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