In a trapezium ABCD, side AB is parallel to side DC; and the diagonals AC and BD intersect each other at point P. Prove that: (i) ∆APB is similar to ∆CPD (ii) PA × PD = PB × PC
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Sir vedio karke samjhate ho to jaida achhe se samajh ate hai
ReplyDeleteOK next time I will try
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