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19 Feb 2022

asin(theta) + bcos(theta) = c then express acos(theta) - bsin(theta) in terms of a, b and C

asin(theta) + bcos(theta) = c then express acos(theta) - bsin(theta) in terms of a, b and C

at February 19, 2022

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Labels: Class 10, Trigonometry

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Find angle theta? Very good math

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asin(theta) + bcos(theta) = c then express acos(theta) - bsin(theta) in terms of a, b and C
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