19 Feb 2022

x^2-yz/a = y^2-zx/b =z^2-xy/c then prove (a+b+c) (x+y+z) =(ax+by+cz)

 

x^2-yz/a = y^2-zx/b =z^2-xy/c then prove (a+b+c) (x+y+z) =(ax+by+cz)



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