18 Jun 2022

32 sin^6 theta= 10 - 15cos 2 theta + bcos 4 theta - acos 6 theta then prove tan theta tan 5 theta = a+b-5/a-b+7

 

32 sin^6 theta= 10 - 15cos 2 theta + bcos 4 theta - acos 6 theta then prove tan theta tan 5 theta = a+b-5/a-b+7



at
Labels: ,

No comments:

Post a Comment

Please do not enter any spam link

Subscribe to: Post Comments (Atom)