28 Jul 2022

In the following figure, ABCD is a cyclic quadrilateral in which AD is parallel to BC. If the bisector of angle A meet BC at point E and the given circle at point F, prove that: (i) EF = FC (ii) BF =DF

 

In the following figure, ABCD is a cyclic quadrilateral in which AD is parallel to BC. If the bisector of angle A meet BC at point E and the given circle at point F, prove that: (i) EF = FC (ii) BF =DF
In the following figure, ABCD is a cyclic quadrilateral in which AD is parallel to BC. If the bisector of angle A meet BC at point E and the given circle at point F, prove that: (i) EF = FC (ii) BF =DF



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