25 Nov 2022

In a Triangle ABC, the equation of the perpendicular bisector of AC is 3x-2y+8=0. If the coordinate of the point A and B are (1,-1) and (3,1) respectively, then the equation of the line BC and the centre of circum circle of the triangle ABC will be

 

In a Triangle ABC, the equation of the perpendicular bisector of AC is 3x-2y+8=0. If the coordinate of the point A and B are (1,-1) and (3,1) respectively, then the equation of the line BC and the centre of circum circle of the triangle ABC will be
In a Triangle ABC, the equation of the perpendicular bisector of AC is 3x-2y+8=0. If the coordinate of the point A and B are (1,-1) and (3,1) respectively, then the equation of the line BC and the centre of circum circle of the triangle ABC will be
In a Triangle ABC, the equation of the perpendicular bisector of AC is 3x-2y+8=0. If the coordinate of the point A and B are (1,-1) and (3,1) respectively, then the equation of the line BC and the centre of circum circle of the triangle ABC will be





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